a Given that Ka for HBrO is 28Solution a Kb KwKa 101428 x
(a.) Given that Ka for HBrO is 2.8
Solution
(a) Kb = Kw/Ka = 10^(-14)/2.8 x 10^(-9)
= 3.6 x 10^(-6)
(b) Ka = Kw/Kb = 10^(-14)/6.3 x 10^(-4)
= 1.6 x 10^(-11)

(a.) Given that Ka for HBrO is 2.8
(a) Kb = Kw/Ka = 10^(-14)/2.8 x 10^(-9)
= 3.6 x 10^(-6)
(b) Ka = Kw/Kb = 10^(-14)/6.3 x 10^(-4)
= 1.6 x 10^(-11)
