Find the volume of the solid in the first octant bounded by
Find the volume of the solid in the first octant bounded by the parabolic cylinder z = 16 - x2 and the plane y = 3.
Solution
some integrating, because y is not a function of x, it matters not what you integrate with respect to first, so the volume is the U(U(25-x^2,y,0,2),x,0,5) where U is the integral sign. Answer: 166.667!!!