What is the output of the above lines of code If you could e

What is the output of the above lines of code?

If you could explain why, that\'d be great!

cout (x+y+z); int x 8, y 3; cout x/y and x%y int x 5, y 25; cout --x y++; cout x y; int x 4; do cout x x 3; while x

Solution

#include <iostream>

using namespace std;

int main()
{

int x=5, &y=x, *z=&y;
x=1;
cout<<(x+y+z);

return 0;
}

sample output

0x7ffcf02b7fb4

#include <iostream>

using namespace std;

int main()
{

int x= 8, y=3;
cout<<x/y <<\"and\" <<x%y;

return 0;
}

sample output

2and2

#include <iostream>

using namespace std;

int main()
{

int x=5, y=25;
cout<<--x <<\'+\' <<y++;
cout<<x <<\'+\' <<y;

return 0;
}

sample output

4+254+26

#include <iostream>

using namespace std;

int main()
{

int x= 4;
do
{
   cout<<x <<\"+\";
   x +=3;
}
while(x<12);

return 0;
}

sample output

4+7+10+

#include <iostream>

using namespace std;

int main()
{

for(int i=20; i>5; i-=3)
   if(i%2==0)
       cout<<2*i <<\"a\";
   else
       cout<<i<<\"b\";
   return 0;
}

sample output

40a17b28a11b16a
  
  
  
int afunc(int a, int& b, int c)
{
   a= 2*a+b;
   b=c;
   cout<<\"afunc:\" <<a <<b <<c;
   return a%2;
  
}
int main()
{
  
   int x=5;
   int y=-2;
   int z=-8;
   x=afunc(x,y,z);
   cout<<\"main:\"<<x <<y <<z;
   return 0;
}

sample output

afunc:8-8-8 main:0-8-8

#include <iostream>

using namespace std;

int main()
{


int x[] = {10, 20, 30};
int *p=x;
cout<< *p + *(p+2)<<endl;
cout<< *p++ <<endl;
p= &x[1];
cout<<++(*p)<<endl;

   return 0;
}

sample output

40
10
21