there are three cards the first is greenSolution15 A event t

there are three cards. the first is green

15)

A= event that at least 2 children have blue eyes

B= event that at least 1 child has blue eyes

Pr(AB)=Pr(AB)/Pr(B)

now here (AB) = A, BECAUSE B IS SUPER SET

THEREFORE Pr(AB)/ Pr(B)=Pr(A)/Pr(B)

THEREFORE P(A) = 3C2*(0.25)^2*(0.75) = 0.140

p(B)= 1- 0.75^5 = 0.763

HENCE 0.140/0.763 = 0.183

B) NOW IT IS GIVEN THAT THE YOUNGEST CHILD HAS BLUE EYES

THEN P(B) = 1

REST P(A) WILL REMAIN SAME

SO THE ANSWER WILL BE 0.140/1 = 0.140