Automobile airbags contain solid sodium azide NaN3 that reac
Solution
The balanced chemical equation for the reaction is given.
2 NaN3 (s) -------> 2 Na (s) + 3 N2 (g)
As per the stoichiometry of the reaction,
2 moles NaN3 = 3 moles N2
Molar mass of NaN3 = (1*22.9897 + 3*14.0067) g/mol = 65.0098 g/mol.
Mole(s) of NaN3 = (26.9 g)/(65.0098 g/mol) = 0.4138 mole.
Mole(s) of N2 produced = (0.4138 mole NaN3)*(3 moles N2/2 moles NaN3) = 0.6207 mole.
Assume the N2 to behave ideally and apply the ideal gas law.
We have
P*V = n*R*T
where P = 1.00 atm; n = 0.6207 mole and T = 22°C = (22 + 273) K = 295 K. Plug in values and obtain
(1.00 atm)*V = (0.6207 mole)*(0.082 L-atm/mol.K)*(295 K)
=====> V = (0.6207 mole)*(0.082 L-atm/mol.K)*(295 K)/(1.00 atm) = 15.0147 L.
The change in volume of the gas = Vf – Vi = (15.0147 L) – (0.0 L) = 15.0147 L (a deflated balloon has zero volume).
The work done, w = -P*V = -(1.00 atm)*(15.0147 L) = -15.0147 L-atm = -(15.0147 L-atm)*(101.33 J/1 L-atm)*(1 kJ/1000 J) = -1.521439551 kJ -1.5214 kJ (ans).
