Find the surface area of the solid generated by rotating abo
Find the surface area of the solid generated by rotating about the x axis and the region bounded by y=cosx, -pi/2 </= x </= pi/2 and the x axis
Solution
S = 2 * int y*(1+(y\')^2) dx (-/2 < x < /2)
We have:
int y*(1+(y\')^2) dx (-/2 < x < /2) =
int cos(x)*(1+(sin(x))^2) dx (-/2 < x < /2) =
2.2956
So we have:
S = 2 * 2.2956 14.4236
