2 Solve the exact differential equation a y2x2dy 2xyxdx 0S
2. Solve the exact differential equation:
a) (y^2+x^2)dy + (2xy+x)dx = 0
Solution
ans)
Geometry also helps. 2xy2xy looks like a diagonal term, rotation by 4545 will simplify the equation. Use
x=u+vx=u+v
y=uvy=uv
(substitution of new variables u=(x+y)/2u=(x+y)/2 and v=(xy)/2v=(xy)/2).
We get
2(u2+v2)(du+dv)2(u2v2)(dudv)=02(u2+v2)(du+dv)2(u2v2)(dudv)=0
v2du+u2dv=0v2du+u2dv=0
This is actually as good as it can possibly get. You can separate the variables!
duu2=dvv2duu2=dvv2
1/u+1/v=C1/u+1/v=C
u+v=Cuvu+v=Cuv
Cx=x2y2
