in the reaction CH3COOHaq KOH aq KCH3COOaq H2Ol If 297 mL

in the reaction CH3COOH(aq) + KOH (aq) ? KCH3COO(aq) + H2O(l) If 29.7 mL of a 0.205 M KOH solution is required to completely neutralize 25.0 mL of a solution of CH3COOH, what is the molarity of the acetic acid solution?

Solution

molarity of acetic acid solution: 5% = 50g/litre Molar mass acetic acid = 60.05 g mol?1 Molarity = 50/60.05 = 0.833M Balanced equation = CH3COOH + NaOH ? CH3COONa + H2O Molar ratio = 1:1 Use equation: M1V1 = M2V2 0.833 *V1 = 25*0.1 V1 = 2.5/0.833 V1 = 3.00ml