The Laplace transform for et is 1s 12 1s 1 1s 12 1s2 1 1
The Laplace transform for e^-t is 1/(s - 1)^2 1/s - 1 1/(s + 1)^2 1/s^2 - 1 1/s + 1
Solution
We know that
Laplace transform of eat is ,
L{eat} = 1/(s - a)
Hence ,
L{e-t} = 1/(s - (-1))
L{e-t} = 1/(s + 1)
Therefore ,
Option \" E \" is correct answer
