I HAVE TO USE APPLET NOT JFRAME JPANEL OR ANYTHING ELSE I HA

************************************************I HAVE TO USE APPLET, NOT JFRAME, JPANEL, OR ANYTHING ELSE. I HAVE TO USE APPLET. AND I HAVE TO USE THE METHODS HE GIVES IN THE HINT SECTION. ALSO I HAVE LOOKED AT OTHER CHEGG ANSWERS ON THIS WEBSITE AND THEY DO NOT USE APPLET. I NEED TO USE APPLET. PLEASE DO NOT JUST COPY AND PASTE ANOTHER ANSWER FROM SOMEWHERE ELSE UNLESS YOU ARE USING APPLET!!!!!*******************************************************

Objective:

Write a program in which draws (yes it actually makes a picture) a triangular fractal using recursion. This is best if done using a java applet.

Suggested Methodology

The idea for it is this

First draw a filled equilateral triangle

Next draw another filled equilateral triangle of a different color that’s upside down in the middle of that triangle

Using the other triangles formed repeat step 2 until a pixel limit of 4 is reached

HINTS:

It may be a good idea to look at the examples I gave 02/12/2015

The method fillPolygon(int[] xPoints, int[] yPoint, numberOfPoints) as called by the graphics device is important

The method setColor(Color aColor) is important for picking different colors to draw things.

Example Image of Results:

Solution

import java.awt.*;

import java.applet.*;

public class SierpinskiTriangle extends Applet private Graphics g;

private int dMin=4; // limit to recursion in pixels

public void paint(Graphics g)

this.g = g;

int d = 1024; // basis (width of the triangle)

int x0 = 50; // distance from the left

int y0 = 50; // distance from the top

int h = (int)(d*Math.sqrt(3)/2); // height // so: suitable for an equilateral triangle

int xA=x0, yA=y0+h; // (bottom-left)

int xB=x0+d, yB=y0+h; // (bottom-right)

int xC=x0+d/2, yC=y0; // equilateral triangle (top-center)

int[] x = xA, xB, xC ;

int[] y = yA, yB, yC ;

drawSierpinskiTriangle( x, y, d/2 ); // start recursion

private void drawSierpinskiTriangle ( int[] x, int[] y, int d )

if (d<=dMin) g.fillPolygon ( x, y, 3 ); // bottom of the recursion else