CH3 CH3 H2C In the above reaction triethylboron reacts with
CH3 CH3 H2C In the above reaction, triethylboron reacts with acetic acid in an organic solvent to form [ethanoyl)oxy](diethyl)borane plus ethane gas. Predict whether the following would increase, decrease or have no effect on the rate of reaction: A. Placing the reaction vessel in a heating mantle and increasing the temperature from 25°C to 75°C. B. Diluting the reactants by adding additional solvent. C. Placing the reaction in an ice bath D. Adding a catalyst E. Doubling the concentration of acetic acid.
Solution
A) rate of reaction increases as temperature is increased
Because more collisions take place results in more reaction
B)diluting the reactants using solvent decreases viscosity of the reactants solution therfore more diffusion takes place and rate of reaction increases
C)cooling the reactor decreses rate of reaction as mentioned in answer option A
D)adding a catalyst increase reaction rate . It increase surface area for reaction to take place .
E) increasing the concentration of reactants increases rate
As in the rate equation ..it is directly proportional to concentraion of reactants
borane plus ethane gas. Predict w CH3 CH3 H2C In the above reaction, triethylboron reacts with acetic acid in an organic solvent to form [ethanoyl)oxy](diethyl)borane plus ethane gas. Predict w](/WebImages/36/ch3-ch3-h2c-in-the-above-reaction-triethylboron-reacts-with-1107254-1761586312-0.webp)