Proof xRif0

Proof

xR,if0<x2,then3<2x.

Solution

Given statement is : xR,if0<x2,then3<2x.

which means; for all x belonging to real number

if x-2 > 0 or x > 2

then given 2x > 3 where x R

As it is clear that for any real value of x ( i.e. x = 2.1 , 2.5 , 3 , 3.2 , 4 ,......)

we always get the product 2x greater than 3.

Hence proved......