A Ferris wheel at a carnival has a diameter of 52 feet Suppo

A Ferris wheel at a carnival has a diameter of 52 feet. Suppose a passenger is traveling at 6 miles per hour. (A useful fact: 1 mi = 5280 ft.) (a) Find the angular speed of the wheel in radians per minute. (b) Find the number of revolutions the wheel makes per hour. (Assume the wheel does not stop.) Do not round any intermediate computations, and round your answer to the nearest whole number. (a) Angular speed: radians per minute (b) Number of revolutions per hour:

Solution

diameter = 52 feet

travelleing at 6 miles / hour

converting miles / hour to feet / minute

6 miles / hour = 6*5280 feet / minute = 31680 feet / minute

angular speed = (speed in feet/minute)/radius = 31680/26 = 1218.46 = 1219 rad/minute

b) No. of rev per minute = 1218.46/2pi = 193.92 rev/minute = 11635.2 rev/hr = 11635 rev/hr