If u 102 and v1120 find distance beetwen u and vSolutionGiv

If u = (-1,0,2) and v=(1,1,20) find distance beetwen u and v.

Given u={-1,0,2}

V={1,120}

Let u=(x1,y1,z1)=(-1,0,2)

v=(x2,y2,z2)=(1,1,20)

Distance between any two points={(x2-x1)^2+(y2-y1)^2+(z2-z1)^2}

Distance between u and v ={(1-(-1))^2+(1-0)^2+(20-2)^2}

D={(1+1)^2+(1)^2+(18)^2}

D={(2)^2+1+324}

D={4+1+324}

D=(329)

D=18.13 squnit

Therefore distance between u and v= 18.13