How many different arrangements of the letters in the word p
How many different arrangements of the letters in the word \"peanut\" are possible?
Solution
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Given word PEANUT
Since no alphabet is repeated in this 6 letter word. Hence these 6 characters have to re arrange themselves for different arrangements.
Total Number of arrangements for 6 letters = 6! (i.e. 6 factorial)
= 6 X 5 X 4 X 3 X 2 X 1
= 720 Solution
