How many 4element DNA sequences Do not contain the base T Co
Solution
We are given 4-element DNA sequences
(a)
we know that there are four bases A , C , T and G
and bases can be repeated
so, if there is on T
it means that we have 3 bases with 4 places to arrange
so, number of ways that do not have base T = 3*3*3*3=3^4
number of ways that do not have base T=81.......Answer
(B)
we know that there are four letters
amnd there are four positions
It means that each letters will be exactly once used
so, number of ways of having all four bases A , T , C and G = 4*3*2*1
number of ways of having all four bases A , T , C and G=24...........Answer
(C)
we know that
There are 4 ways of choosing which base (A, C, G, or T) represents the pair
There are 4 choose 3 = 4 ways of choosing which 3 positions in the 4-element sequence are occupied by the pair
Once the pair has been established, there are 2 ways of choosing the base for the first of the remaining 2 unoccupied positions
2 ways of choosing the base for the remaining unoccupied position
so, we get
number of wyas = 4*3*2*2=48 ........Answer
