Homework SourseAt a time t seconds after it is thrown up in the air a tomat
At a time t seconds after it is thrown up in the air, a tomato is at a height (in meters) of f(t)=?49t^2+65t+3 m.
C. What is the acceleration at t=5? (Include units.)
D. How high does the tomato go? (Include units.)
C. What is the acceleration at t=5? (Include units.)
D. How high does the tomato go? (Include units.)
Solution
Let height be h (t) Part 1 h (t) = - 49 t ² + 55 t + 5 h ` (t) = - 98 t + 55 h \" (t) = - 98 h \" (4) = - 98 (acceleration at t = 4) Part 2 Turning point when h ` (t) = 0 - 98 t + 55 = 0 98 t = 55 t = 55 / 98 h (55 / 98) = - 49 (55/98)² + 55(55/98) + 5 h (55 / 98) = - 15.4 + 30.9 + 5 h (55 / 98) = 20.5 Reaches a height of 20.5 m Part 3 in air for 110 / 98 sec = 55 / 48 sec
