How much power is required for the motor to rotate the syste

How much power is required for the motor to rotate the system? (You can assume any diameter for the motor and system gears)

Solution

GIVEN & ASSUMPTIONS:- Speed of rotating system = 100 RPM and let angular acceleration \'a\' = 1 rad/s2, Motor pulley diameter = 0.4m and system pulley diameter = 0.6m, The 3 individual masses can be converted into a single mass ring of 300 kg

SOLUTION:- Radius \'r\' of the rotating system r = 1 / Cos(30) = 1/0.866 = 1.15m

So the inertia I of the ring = 300 x (1.15)^2 / 2 = 198.4 kg.m

So torque required to rotate the system Ts = I x a = 198.4 x 1 = 198.4 Nm

Since system pulley rotates at 100 rpm, so motor pulley will rotate at (100 x 0.3) / 0.2 = 150rpm

So finally the power required at motor Pm = 0.105 x Tm x 150 = 0.105 x 198.4 x 150 = 3124.8 Watts

So Motor Power required Pm = 3125 W = 3.12 KW (ANSWER)