Calculate delta G for Cus lCu2 10M ll zn210M l Zns cell pote

Calculate delta G for Cu(s) lCu^2 (.10M) ll zn^2(.10M) l Zn(s) cell potential is .44 volts

Solution

Delta G= -nFE
= -(2) (96,485) (.44)
= 84,906.8 J
= 84.9 kJ