plz help me The position as a function of time xt yt y of a

plz help me......!

The position as a function of time (x(t), y(t)) y, of a projectile fired with a speed of v_0 at an angle alpha is given by x(t) - v_0 cos alpha t y(t) = v_0sin alpha. t-1/2gt^2 where g = 9.81 m/s^2. The polar coordinates of the projectile at time t are (r(t).Theta(t)), where r(t) = Squareroot x(t)^2 + y(t)^2 and tan theta (t) = y(t)/x(t).Consider the case wherev_0 = 162 m/s and alpha = 70degree Determine r(t) and Theta(t) for t = 1, 6, 11....., 31s.

Solution

%start the script

G=9.81;

V0=162;

Alpha=70;

T=1:5:31

T= columns 1 through 6

1 6 11 16 21 26

Column 7

31

X _t=VO *cosd (alpha)*t;

Y_t= (VO*Sind (alpha)*t)-((1/2)*g*(t. ^2));

R_t=sqrt ((c_ t. ^2) + (y_ t. ^2))

R_t=

1.0e+03*

Columns 1 through 3

0.1574 0.8083   1.2410

Columns 4 through 6

1.4759 1.5564   1.5773

Column 7

1.7176

Thete_t=atand((y_t)./(x_t))

Theta_t=

Columns 1 through 3

69.3893 65.7152   60.5858

Colums 4 through 6

53.0831 41.6187    24.0270

Column 7

01812

Mat lab output:

R_t=1.0e+003*

0.1574 0.8083   1.2410   1.4759   1.5564    1.5773 1.7176

Theta_t=

69.3893 65.7152 60.5858 53.0831 41.6187 24.0270 0.1812