Find the equation of a line parallel to 3x 6y 5 and passin

Find the equation of a line parallel to 3x - 6y = 5 and passing through (-2, -3). Write the equation in slope-intercept form. Find the equation of the line parallel to y = -3x + 7 with y-intercept 1. Find the equation of a line with x-intercept 3 and y-intercept -6 Find the equation of a line with y-intercept -4 and perpendicular to 2x + 3y = 5. Find the equation of the line parallel to 4x + 3y = 12 and passing through (-3, 2). Find the equation of a line perpendicular to 3x - 2y = 8 and passing through (-1, -2). Write the equation in slope-intercept form. Find the equation of a line parallel to 2x + 3y = 6 and passing through (-2, -3). Write the equation in slope-intercept form. Find the equation of the line through (3, -2) and parallel to the line through (-2, 4) and (-4, -2).

Solution

2.

equation of line is given by:

y = mx + c

c = y-intercept = 1

the parallel line means slope will be same as the given line\'s slope

m = -3

So equation of line:

y = -3x + 1

3.

y-intercept = -6

x-intercept = 3

equation of line is:

y = mx + c

c = -6,

when y = 0, x = 3, So

0 = m*3 - 6

m = 2

equation of line will be

y = 2x - 6

4.

perpendicular line means m1*m2 = -1

m1 = slope of given line

2x + 3y = 5

3y = -2x + 5

y = (-2/3)x + 5/3

m1 = -2/3

m2 = -1*(-3/2) = 3/2

y-intercept = -4

equation of line:

y = 3x/2 - 4

3x - 2y = 4