Teta07853 Solution for a Xt1sin 4t07853 Please solve for bcd

Solution

a)

X(t) = 1*sin(4t + 0.7853 )

b)

amplitude = 1 ft

period = 2*pi/(4) = 1.571 s

frequency = 1/period = 1/1.571 = 0.637 Hz

c)

for returning to same position in 1 time period

So, answer is t = 1.571 s

d)

time required, t = T/4 = 1.571/4 = 0.392 s

e)

at t = 3*pi/16,

v = 1*4*cos(4*3*pi/16 + 0.7853)

= -4 m/s

f)

for v = 0

4*t + 0.7853 = pi/2

So, t = 0.196 s <------answer