A solution contains 0035 M Ag and 0037 M Pb2 If you add ClS

A solution contains 0.035 M Ag and 0.037 M Pb2 . If you add Cl

Solution

K AgI = [Ag+] [I-] 8.3e-17 = [Ag+] [I-] 8.3e-17 = [2.1 e?4] [I-] [I-] = 3,95e-13 Molar Iodide is needed to saturate the sol\'n ====================== K PbI2 = [Pb+2] [I-]2 7.9 e -9= [Pb+2] [I-]2 7.9 e -9= [1.7
 A solution contains 0.035 M Ag and 0.037 M Pb2 . If you add ClSolution K AgI = [Ag+] [I-] 8.3e-17 = [Ag+] [I-] 8.3e-17 = [2.1 e?4] [I-] [I-] = 3,95e-13 Molar I

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