Calculate the following in 779 g Li3PO4 Number a Li ions Li

Calculate the following in 7.79 g Li3PO4 Number a) Li ions Li ions Number b) grams O + Previous :weUpanewscedion next Check Answer Exit - Hint rch De

a) 115.6 g of Li3PO4 = 1 mole

7.79 g of Li3PO4 = 1x 7.79/115.6 = 0.0674 mole

1mole of Li3PO4 contains Li ions = 3 Li+ ions

0.0674 mole contains = 0.0674 x3 Li+ mole = 0.2022 Li + mole

1 mole = 6.02*10^22 ions

0.2022 X 6.023x10^23 = 1.22 x10^22 Li^+ ions

b) 115.6 g of Li3PO4 contains grams of O = 64g

1g of Li3PO4 contains O = 64/115.6 g

7.79 g of Li3PO4 contains O = 64 x 7.79/115.6 = 4.31 g of O