Calculate the standard free energy of formation of 2 mol of

Calculate the standard free energy of formation of 2 mol of AgCl(s) at 25

Solution

2Ag + Cl2 =>2AgCl


delta(H) = -127.07*2= -254.14 Kj

delta(s) =2(96.2-42.55)-222.96 = -115.66j

del(G) =del(H)- Tsel(S) = -288.6KJ

Calculate the standard free energy of formation of 2 mol of AgCl(s) at 25Solution2Ag + Cl2 =>2AgCl delta(H) = -127.07*2= -254.14 Kj delta(s) =2(96.2-42.55)-2

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