What is the volume in L of 0679 moles of O2 gas having a tem

What is the volume, in L, of 0.679 moles of O2 gas having a temperature of 68.9 ºC and pressure of 5.79 atm?

PV = nRT

where, P = pressure = 5.79 atm

V = volume = ?

n = number of moles = 0.679 mol

R = Gas constant

T = temperature = 68.9 + 273 = 341.9 K

5.79 * V = 0.679 * 0.0821* 341.9

5.79 * V = 19.1

V = 19.1 / 5.79 = 3.30 L

Therefore, the volume of gas is 3.30 L