Use the substitution u e2x3y5 to solve 3 dydx 42e2xe2x3y52
     Use the substitution u= e^2x-3y+5 to solve 3 dy/dx = [4+2e^2x-(e^2x-3y+5)^2].  A parachutist with a total weight of 160 lbs falls from rest toward the earth. After 5 seconds the chute immediately opens and the chutist\'s GPS registered a velocity of 126 ft/sec. The chute leads to a drag resistance (in units of Ib-ft/sec^2 that is equal to 5/8V^2(t), where V(t) is the velocity of the parachutist at any time. Find the velocity of the parachutist at any time t.![Use the substitution u= e^2x-3y+5 to solve 3 dy/dx = [4+2e^2x-(e^2x-3y+5)^2]. A parachutist with a total weight of 160 lbs falls from rest toward the earth. Af  Use the substitution u= e^2x-3y+5 to solve 3 dy/dx = [4+2e^2x-(e^2x-3y+5)^2]. A parachutist with a total weight of 160 lbs falls from rest toward the earth. Af](/WebImages/36/use-the-substitution-u-e2x3y5-to-solve-3-dydx-42e2xe2x3y52-1108403-1761587132-0.webp) 
  
  Solution
you can find velocity by
this mehod
you can also solve it for
displacement vertically
your mehod iscorrect
and you hav solved correctly
![Use the substitution u= e^2x-3y+5 to solve 3 dy/dx = [4+2e^2x-(e^2x-3y+5)^2]. A parachutist with a total weight of 160 lbs falls from rest toward the earth. Af  Use the substitution u= e^2x-3y+5 to solve 3 dy/dx = [4+2e^2x-(e^2x-3y+5)^2]. A parachutist with a total weight of 160 lbs falls from rest toward the earth. Af](/WebImages/36/use-the-substitution-u-e2x3y5-to-solve-3-dydx-42e2xe2x3y52-1108403-1761587132-0.webp)
