Solve for x log3 x 8 log3 x 2SolutionLog 3x8 log 3x 2 L
Solve for x: log_3 (x - 8) + log_3 x = 2
Solution
Log 3(x-8) + log 3(x) = 2
Log 3( (x-8)(x))= 2
(x-8)(x) = 32
(x-8)(x)= 9
x 2 -8x -9=0
Solving this quadratic equation, we get
x=9 , -1
Since x can\'t be negative because of logarithm properties.
So, x= 9
