For y sin10x pi3 its amplitude is its period is its phase
For y = sin(10x + pi/3), its amplitude is its period is its phase shift is
Solution
y = sin (10x + pi/3 ) + D
standard function is given by
y = a sin ( Bx - C)
a = amplitude
amplitude = 1
period = 2pi/ B = 2pi/10 = pi/5
phase shift = C/B = - pi/30
