For y sin10x pi3 its amplitude is its period is its phase

For y = sin(10x + pi/3), its amplitude is its period is its phase shift is

Solution

y = sin (10x + pi/3 ) + D

standard function is given by

y = a sin ( Bx - C)

a = amplitude

amplitude = 1

period = 2pi/ B = 2pi/10 = pi/5

phase shift = C/B = - pi/30

 For y = sin(10x + pi/3), its amplitude is its period is its phase shift is Solutiony = sin (10x + pi/3 ) + D standard function is given by y = a sin ( Bx - C)

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