We have the following C code in a function main string stra

We have the following C++ code in a function main():

string str_a = \"ABCDE\" ;

   string str_b = \"XYZUV\" ;

   string str_c = \"TAMU\" ;

   string * ptr1 = NULL;

   string * ptr2 = &str_b ;

   ptr1 = &str_a ;

   ptr1 = &str_c ;

   cout << *ptr1 << endl;

   cout << ptr1 << endl;

   cout << *ptr2 << endl;

   cout << ptr2 << endl;

What would be displayed when the above code segment is executed?

(a)

NULL

{the address of str_a}

XYZUV

{the address of str_b}

                                             

(b)

{the address of str_a}

ABCDE

{the address of str_b}

                                             

(c)

ABCDE

{the address of str_a}

XYZUV

{the address of str_b}

                                             

(d)

TAMU

{the address of str_c}

XYZUV

{the address of str_b}

                                               

(e)

ABCDE

XYZUV

{the address of str_a}

{the address of str_b}

                                             

(f)

TAMU

{the address of str_c}

ABCDE

{the address of str_a}

                                             

(g) None of (a) through (f) is a correct answer.

Solution

Answer:D

(d)

TAMU

{the address of str_c}

XYZUV

{the address of str_b}

Explanation:

string * ptr1 = NULL;

   string * ptr2 = &str_b ;

   ptr1 = &str_a ;

   ptr1 = &str_c ;

   cout << *ptr1 << endl;

   cout << ptr1 << endl;

   cout << *ptr2 << endl;

   cout << ptr2 << endl;

In first line ptr1 assigned with NULL

in line 2, ptr2 value assigned with str_b. So now ptr2 value is XYZUV

in line 3, ptr1 value is assigned with str_a. so ptr1 value is ABCDE

in line 3, ptr1 value is assigned with str_c. so ptr1 value is TAMU

So finally ptr1 value is TAMU and ptr2 value is XYZUV