1 A reaction is third order for reactant A and zero order fo

1. A reaction is third order for reactant A and zero order for reactant B. If you quadruple the concentration of A, what happens to the reaction rate? If you quadruple the concentration of B, what happens to the reaction rate? 2. Considering the following reaction: 3(aq) + 5 Br(aq) + 6H(aq) 3 Br2(aq) + 3H2O Using the data in the following table, find the rate law equation, k and the order of the reaction with respect to each reactant as well as the overall order. (Use whole numbers or common fractions for order: eg. 1.11 would be considered first order and 0.333 would be Exp. Number Bro] (r] (ml) [H+] (l) Initial Rate (10-3 mol) 0.10 0.20 0.10 0.20 0.10 0.10 0.30 0.10 0.10 0.10 0.10 0.15 1.2 2.4 3.5 5.4 4

Solution

1)
a)
Given Rate law is:
rate = k[A]^3
rate new / rate old = ([A]new/[A]old)^3*([B]new/[B]old)^0
here:
[A]new/[A]old = 4
[B]new/[B]old = 1
putting values
rate new / rate old = (4)^3*(1)^0
rate new / rate old = 64*1
rate new / rate old = 64
Answer: rate increases by 64 times

b)
Given Rate law is:
rate = k[A]^3
rate new / rate old = ([A]new/[A]old)^3*([B]new/[B]old)^0
here:
[A]new/[A]old = 1
[B]new/[B]old = 4
putting values
rate new / rate old = (1)^3*(4)^0
rate new / rate old = 1*1
rate new / rate old = 1
Answer: rate will not change

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