1 If tan 125 and is in quadrant IV find the values of the re
Solution
Let = P = Perpendicular
B = Base
H = Hypotenuse
1) tan = -12/5 = P/B
Here P = 12, B = 5 ======> H = sqrt(12^2 + 5^2) = 13
Then
Sin = P/H = -12/13
Cos = B/H = 5/13
Csc = 1/sin = -13/12
Sec = 1/cos = 13/5
Cot = 1/tan = -5/12
2) cos = -4/5 = B/H
Here B = 4, H = 5 ======> P = sqrt(5^2 - 4^2) = 3
Then
Sin = P/H = 3/5
tan = P/A = -3/4
Csc = 1/sin = 5/3
Sec = 1/cos = -5/4
Cot = 1/tan = -4/3
3) sin = 1/6 = P/H
Here P = 1, H = 6 ======> B = sqrt(6^2 - 1^2) = sqrt(35)
Then
cos = B/H = -sqrt(35)/6
tan = P/A = -1/sqrt(35)
Csc = 1/sin = 6
Sec = 1/cos = -6/sqrt(35)
Cot = 1/tan = - sqrt(35)
4) tan = 2/3 = P/B
Here P = 2, B = 3 ======> H = sqrt(2^2 + 3^2) = sqrt(13)
Then
Sin = P/H = -2/sqrt(13)
Cos = B/H = -3/sqrt(13)
Csc = 1/sin = - sqrt(13)/2
Sec = 1/cos = - sqrt(13)/3
Cot = 1/tan = 3/2

