In a population of peppered moths 25 of the population shows
Solution
As 25% of population show recessive phenotye of white.
a. The variable 25% represents aa (Recessive Phenotype)
b. The frequency of aa is 25%, which means that q2 = 0.25, by definition. If q2 = 0.25, then q = 0.5, again by definition. Since q equals the frequency of the a allele, then the frequency is 50%.
c. Since q = 0.5, and p + q = 1, then p = 0.5
d. Population has 1500 moths and it is already given that 25% are recessive, hence aa=25%
No. of moths with homozygous recessive condition (aa) = 25% of Total number of moths
= 25 x1500
100
= 375 moths
No. of moths with homozygous dominant condition (AA) ( As the frequency of p was calculated earlier, we will work with that value, p=0.5 , therefore, p2 = 0.5x0.5 =0.25 . The frequency of AA is 25%.
So, as in earlier step, the no. of moths with homozygous dominant condition are 25% of total no. of moths = 375 moths.
No. of moths with heterozygous confition (Aa) = Total no. of moths - ( No. of homozygous dominant+ No. of homozygous recessive moths)
= 1500 - (375+375)
= 750 moths
No. of homozygous recessive moths = 375
No. of homozygous dominant moths = 375
No. of heterozygous moths = 750
