Find the critical numbers of fx x3 x2 XSolution To find th
Find the critical numbers of :
f(x)= x^3 + x^2+ X
f(x)= x^3 + x^2+ X
Solution
To find the critical values of the function, take a derivative of the function and make f\'(x) = 0. f\'(x) = 3x² + 2x + 1 0 = 3x² + 2x + 1 Apply quadratic formula. ax² + bx + c = 0 Let: a = 3 b = 2 c = 1 x = [-2 ± v(2)² - 4(3)(1)]/2(3) x = [-2 ± v8 - 12]/6 x = [-2 ± 2iv3]/6 x = [-1 ± iv3]/3 There are critical values at x = [-1 ± iv3]/3.