Find the critical numbers of fx x3 x2 XSolution To find th

Find the critical numbers of :

f(x)= x^3 + x^2+ X

Solution

To find the critical values of the function, take a derivative of the function and make f\'(x) = 0. f\'(x) = 3x² + 2x + 1 0 = 3x² + 2x + 1 Apply quadratic formula. ax² + bx + c = 0 Let: a = 3 b = 2 c = 1 x = [-2 ± v(2)² - 4(3)(1)]/2(3) x = [-2 ± v8 - 12]/6 x = [-2 ± 2iv3]/6 x = [-1 ± iv3]/3 There are critical values at x = [-1 ± iv3]/3.
Find the critical numbers of : f(x)= x^3 + x^2+ XSolution To find the critical values of the function, take a derivative of the function and make f\'(x) = 0. f\

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