Use lhospitals rule to find the limit limit as y approaches

Use l\'hospitals rule to find the limit.
limit as y approaches 0
(sqrt(3y+16)-4)/y

given limit is in indeterminate form 0/0 so applying l hospital rule differentiate both numerator and denominator wrt y differentiation of numerator gives (1/2*sqrt(3y+16)*3 and differentiation of denominator gives 1 hence limit =3/8

$Use l\'hospitals rule to find the limit. limit as y approaches 0 (sqrt(3y+16)-4)/ySolution given limit is in indeterminate form 0/0 so applying l hospital rule$

Use lhospitals rule to find the limit limit as y approaches

Solution

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