Find the area under y4sinx and above y4cosx for pi2sinx So t

Find the area under y=4sinx and above y=4cosx for pi/2<=x<=3pi/2. (Note that this area may not be defined over the entire interval.)

area =

Solution

between /2 and 5/4, sin(x)>cos(x) and in the rest cos(x)>sin(x)

So the area is

4[/25/4 sin(x)-cos(x)+5/43/2 cos(x)-sin(x) dx=

4(-cos(x)-sin(x)|/25/4 +sin(x)+cos(x)|5/43/2

=4(sqrt(2)+1-1+sqrt(2))=8sqrt(2)

Find the area under y=4sinx and above y=4cosx for pi/2<=x<=3pi/2. (Note that this area may not be defined over the entire interval.) area =Solutionbetween

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