Find the area under y4sinx and above y4cosx for pi2sinx So t
Find the area under y=4sinx and above y=4cosx for pi/2<=x<=3pi/2. (Note that this area may not be defined over the entire interval.)
area =
area =
Solution
between /2 and 5/4, sin(x)>cos(x) and in the rest cos(x)>sin(x)
So the area is
4[/25/4 sin(x)-cos(x)+5/43/2 cos(x)-sin(x) dx=
4(-cos(x)-sin(x)|/25/4 +sin(x)+cos(x)|5/43/2
=4(sqrt(2)+1-1+sqrt(2))=8sqrt(2)
