At equilibrium the concentrations in this system were found
At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.100 M and [NO]=0.500 M.
N2(g) + O2(g) <=> 2NO(g)
If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium is re-established?
Solution
Kc= 0.5/0.1*0.1 = 50
N2(g) + O2(g) <=> 2NO(g)
0.1+x/2 0.1+x/2 0.8-x
50= 0.8-x / 0.1+x/2 ^2
![At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.100 M and [NO]=0.500 M. N2(g) + O2(g) <=> 2NO(g) If more NO is added, brin At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.100 M and [NO]=0.500 M. N2(g) + O2(g) <=> 2NO(g) If more NO is added, brin](/WebImages/36/at-equilibrium-the-concentrations-in-this-system-were-found-1109041-1761587596-0.webp)