At equilibrium the concentrations in this system were found

At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.100 M and [NO]=0.500 M.

N2(g) + O2(g) <=> 2NO(g)

If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium is re-established?

Solution

Kc= 0.5/0.1*0.1 = 50


N2(g) + O2(g) <=> 2NO(g)

0.1+x/2 0.1+x/2 0.8-x


50= 0.8-x / 0.1+x/2 ^2

 At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.100 M and [NO]=0.500 M. N2(g) + O2(g) <=> 2NO(g) If more NO is added, brin

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