KP 0029 at 572 K for the reaction 2 HI g H2 g I2 g At equi

KP = 0.029 at 572 K for the reaction 2 HI (g) <--> H2 (g) + I2 (g). At equilibrium, the partial pressure of H2 is 0.875 atm and the partial pressure of I2 is 0.465 atm. What is the partial pressure of HI in atm?

Solution

2HI(g) <---> H2(g) + I2(g)

Kp = pH2*pI2/(pHI)²

p(HI)² = pH2*pI2/Kp = 0.875atm*0.465atm/0.029

pHI² = 14.03

pHI = (14.03)² = 3.75atm