The threestation work cell illustrated in the figure below h
The three-station work cell illustrated in the figure below has a product that must go through one of the two machines at station 1 (they are parallel) before proceeding to station 2.
A) The bottleneck time of the system is ___minutes per unit (enter your response as a whole number).
B) ____ is the bottleneck station
C) The throughput time is ____minutes (enter your response as a whole number).
D) If the firm operates 8 hours per day, 5 days per week, the weekly capacity of this work cell is___ units (enter your response as a whole number).
Please I need the the correct answer will give thumbs up.
Capacity: 30 units/hr Station 1 Machine A Station 2 Station 3 Station 1 Machine B Capacity: 30 units/hr CapacityCapacity: 3 units/hr 15 units/hrSolution
The bottleneck station will be the one which has maximum processing time and hence produces minimum number of units per hour .
In the given example , it is Station 2 which produces minimum number of 3 units per hour.
Therefore, bottleneck station is Station 2
The bottleneck time will be = 60 minutes/ 3 units = 20 minutes/ unit
THE BOTTLENECK TIME OF THE SYSTEM IS 20 MINUTES PER UNIT
STATION 2 IS THE BOTTLENECK SYSTEM
The throughput time of the system
= Throughput time of one of the machines in station 1 + Throughput time of machine in station 2 + Throughput time of machine in station 3
= 60 minutes / 30 units + 60 minutes/ 3 units + 60 minutes/ 15 units
= 2 minutes/ unit + 20 minutes/ unit + 4 minutes/ unit
= 26 minutes/ unit
THE THROUGHPUT TIME IS 26 MINUTES
The capacity of the system will be determined by the capacity of the bottleneck process which is station 2 and capacity of the system is 20 minutes / unit
Available period in a week = 8 hours/ day x 5 days = 40 hours = 2400 minutes
Therefore , capacity of the work cell = 2400 minutes/ 20 minutes = 120 units per week
CAPACITY OF THE WORK CELL = 120 UNITS
| THE BOTTLENECK TIME OF THE SYSTEM IS 20 MINUTES PER UNIT |
| STATION 2 IS THE BOTTLENECK SYSTEM |
