Factor the trinomial if possible 6r2 23r 10Solution6r2 23r
Factor the trinomial, if possible
6r2 - 23r + 10
Solution
6r^2 -23r +10
Now check value of b^2 -4ac = sqrt(23^2 - 6*10*4)
= 17
So we can factorise it : r = ( 23 +/- sqrt(23^2 - 6*10*4) )/12
= (23 +/- 17)/12
= 40/12 , 6/12
r = 10/3 ;r = 1/2
So, we can write 6r^2 -23r +10 = ( 3r -10)(2r -1)
