17 What volume of a 0200 M solution of NaCI contains 530 g o

17. What volume of a 0.200 M solution of NaCI contains 53.0 g of NaCI?

Molarity=Number of moles/Volume of the solution in litres

Given molarity=0.2 M

Number of moles of NaCl=weight/molecular weight

=53/58.5 =0.906 moles

volume=number of moles/molarity

=0.906/0.2 =4.53 litres