Suppose ga 025sin26a 15 a What is the argument of the sine

Suppose g(a) = 0.25sin(26a - 15). a. What is the argument of the sine function? (Enter an expression.) b. The argument of the sine function represents what quantity? horizontal distance to the right of the vertical diameter (measured in radius lengths) number of seconds elapsed vertical distance above the horizontal diameter (measured in radius lengths) radius length angle measure (in radians) c. For the value of sine to vary through a complete cycle of its outputs, the value of the argument must increase from 0 to d. For the value of 26a - 15 = 0, the value of a must equal e. For the value of 26a - 15 = 2 pi the value of a must equal f. For the value of sine to vary through a complete cycle of its outputs, the value of the input of g must vary by g. What is the period of the function g?

Solution

#a) The argument is the variable, term or expression on which a function operates.

26a-15 is the argument of this function.

#b) Argument represents radius length.

#c)If we graph it using graphing calculator, one complete cycle of this function is from 0 to 0.24

#d)26a-15=0

Add both sides 15.

26a=15

Divide both sides by 26.

a=0.5769

For #e

26a-15= 2(3.14)

26a-15= 6.28

Add both sides 15.

26a =21.28

Divide both sides by 26.

a =0.8184

#f) According to graph one complete cycle of a sine function takes 0.242 untis.

#g) Period = 2pi /b

Here \'b\' is 0.242

So, use this value to find period.

Period = 2pi/0.242 =8.2645pi