x 2y z 15 5y 2z 16 z 3 a 22 b 16 c 157 d 8 Solve the s

{x + 2y + z = 15 5y - 2z = -16 z = 3. (a) 22 (b) 16 (c) 15/7 (d) 8 Solve the system of linear equations: {2x + y - z = 3 x - 3y + z = 7 3x + 5y - 3z = 0. (a) (-2, -1, -1) (b) Infinitely Many Solutions c) (2, -2, -1) d) No Solution Match the graph with the correct inequality. (a) y x^2 + 3x - 1 (c) y lessthanorequalto x^2 + 3x - 1 (d) y greaterthanorequalto x^2 + 3x - 1 Find the partial fraction decomposition: 12x^2 - 13x - 3/(x - 1)^2 (x + 3) a) 4/x - 1 - 3/(x - 1)^2 + 2/x + 3 b) 6/x + 3 - x + 1/(x - 1)^2 c) 3/x - 1 - 1/(x - 1)^2 + 9/x + 3 d) 4/x - 1 + 3/x + 3 - 3/(x - 1)^2 e) 2/x - 1 + 7/(x - 1)^2 - 2/x + 3. Identify the graph the inequality: (x - 1)^2 + (y + 2)^2 > 4

Solution

2)
2x + y - z = 3
x - 3y + z = 7
3x + 5y - 3z = 0

Add first two :
3x - 2y = 10

Now, multiply the second by 3 :
3x - 9y + 3z = 21
3x + 5y - 3z = 0

Adding these to eliminate z :
6x - 4y = 21

So, we have:
3x - 2y = 10
6x - 4y = 21

Multiply the first of these by 2 :
6x - 4y = 20
6x - 4y = 21

These cannot be simultaneously true

So, NO SOLUTION

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3)
Well, this ones easy..
Notice that the quadratic is graphed with solid lines
So, it cannot be options A or B

And also, notice that we have shaded below the parabola
So, it must be in the form
y <=

So, option C

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5)
(x-1)^2 + (y+2)^2 > 4

This is a circle of center = (1,-2)
and radius = sqrt4 = 2

This is in either A or C

Now, we are shading everywhere outside it

So, option C