Q Ch 14Kinetics Started Feb 25 at 227pm Quiz Instructions DQ

Q. Ch 14-Kinetics Started: Feb 25 at 2:27pm Quiz Instructions DQuestion 8 ne reaction 2N205(- 4N02(g) +02 is first order in Nor For this reaction at 49C the rate constant k . 1.0x10- For a particular experiment (IN,Osl,-10x 10- M, calculate IN,O., after 3.8 x 10 seconds O 11 M O 38M O 2.2 x 10 M O 1.0 x 10 M No new data to save. Last checked at 2:46pm e here to search

Solution

Answer

2.2×10-5M

Explanation

Integrated form of first order equation is

ln[A]t= - kt + ln[A]0

where,

k = rate constant, 1.0×10-5s-1

   t = time, 3.8×10-5s

[A]0 = Initial concentration, 1.0×10-3M

[A]t = Concentration at time t

substituting the values

ln[A]t = - (1.0×10-5s-1 × 3.8×105s) + ln(1.0×10-3M)

2.303log(1.0×10-3M/[A]t) = 3.8

log(1.0×10-3M/[A]t) = 1.65

1.0×10-3M /[A]t = 44.66

[A]t= 2.24×10-5M

 Q. Ch 14-Kinetics Started: Feb 25 at 2:27pm Quiz Instructions DQuestion 8 ne reaction 2N205(- 4N02(g) +02 is first order in Nor For this reaction at 49C the ra

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