Explain your answer 0 2logn4 vs 4nlogn2Solution2 logn4 vs 4

Explain your answer. 0 2log(n^4) vs 4nlog(n^2)

Solution

2 log(n⁴) vs 4 n log(n²).

Using the rule log_b(x ^y) = y log_b(x), we can write our expression as:

2 log(n⁴) as 2 . 4. log n, and

4 n log(n²) as 4 n 2 log n.

Therefore, the LHS equation is: 8 log n, and the RHS equation is 8 n log n.

And, now we can conlude that, 1 (8logn) is of less value, when compared to that of n (8logn).

And therefore, the LHS is more efficient than the RHS.

i.e., 2 log(n⁴) is of better efficiency.