Determine the derivative of fx cos2 x43 6 cos2 x42 sin2 x4
     Determine the derivative of:  f(x) = (cos(2 x-4))^3  -6 (cos(2 x-4)^2) sin(2 x-4)  -6 (cos(2 x-4))^2 sin(2 x-4)  -18 (cos(2 x-4))^2 sin(2 x-4)  -18 (cos(2 x-4))^2  Not listed  -6 (cos(2 x-4))^2 
  
  Solution
using chain rule
f’(x) = d/dx (cos(2x -4))^3
= 3 (cos(2x-4))^2 * d/dx cos(2x-4)
= 3(cos(2x-4))^2 * -sin(2x-4) * d/dx 2x
= 3(cos(2x-4))^2 * -sin(2x-4) * 2
= -6 (cos(2x-4))^2 * -sin(2x-4)

