O 1 whiteeyed notched female 1 wild type female 1 notched ma

O 1 white-eyed notched female 1 wild type female 1 notched male 1 white-eyed male O 1 wild type female 1 notched female 1 white-eyed male O 1 white-eyed female 1 notched female 1 white-eyed male O 1 wild type female 1 notched female 1 white-eyed male 1 white-eyed notched male

Solution

A white eyed notched female would have the genotype: Xw X

and a wild type male would be Xw+ Y

a cross between the two would look like this:

therefore the phenotypes would be : 1 wild type female, 1 notched female, 1 white eyed male

therefore the

	Xw	X
Xw+	Xw+ Xw	Xw+ X
Y	Xw Y	X Y