Homework Sourseconsider the following function fx2x33x272x c Apply the Firs
consider the following function. f(x)=2x^3+3x^2-72x (c) Apply the First Derivative Test to identify the relative extremum. (If an answer does not exist, enter DNE.) relative maximum (x, y) = ( ) relative minimum (x, y) = ( ) Experts only! I will rate
Solution
f\' = 6x^2 + 6x - 72 f\' = 0 for => x = -4 or x = 3 so we have rel max == -4,208 min = 3,-135
